## Matemática => Triángulos => Mensaje iniciado por: jacks en 01 Mayo, 2012, 00:05

 Título: orthocenter Publicado por: jacks en 01 Mayo, 2012, 00:05 If $O$ is the orthocenter of a $\triangle ABC$ having sides $BC\;,CA\;,AB$Where $BC = a\;\;,CA = b\;\;,AB = c$.Then the ratio of radious of circle circumscribing the $\triangle BOC\;\;,\triangle COA\;\;,\triangle AOB$ is Título: Re: orthocenter Publicado por: Luis Fuentes en 04 Mayo, 2012, 07:34 Hello See at the picture:  The points $E,F,G$ are the center of the three circumscribing circles. Proof that the triangle $EFG$ is equal to the triangle $ABC$, and $O$ is its circumcenter. Conclude that the radious of circle circumscribing BOC,COA,AOB,ABC are equal.Best regards. Título: Re: orthocenter Publicado por: jacks en 15 Mayo, 2012, 00:29 Thanks el_manco